Webfunction fixAmt(ether: BigNumber, token: Token, chainId: number): BigNumber { const decimals = token.decimals (chainId) ?? 18 ; if (decimals === 18) { return parseEther (ether.toString ()) } const unit = unitNames [decimals]; return parseUnits (ether.toString (), unit) } Example #20 WebAug 13, 2024 · Khoản đầu tư này sẽ cho phép Nexus Mutual nhận được lợi nhuận từ việc nắm giữ ETH của mình. Nexus Mutual sẽ chuyển 29 triệu đô la trong quỹ kho bạc sang Maple Finance. Theo tài liệu đề xuất, chỉ 20% ether trong quỹ vốn của nó là tạo ra thu nhập cho bảo hiểm DeFi. 20% này có ...
BigNumber - Hethers
WebAug 21, 2024 · The Vconomics application’s launch event provided the foundation for the establishment of a decentralized digital economy. With a variety of appealing features, the product is likely to attract a big number of consumers, resulting in numerous community benefits. The Vconomics app’s vision and mission in a decentralized digital economy. WebFeb 20, 2024 · For my case I needed to add .toString () to the BigNumber before passing it to the contract. async changePayoutAmount_ether (amount_ether) { let amount_wei = new BigNumber (amount_ether).shiftedBy (18).toString () await this.state.pcrContract.methods.setPayoutAmount (amount_wei).send ( {from: … gammage ticket office
Ether jumps to 11-month high in wake of software upgrade
WebOct 31, 2024 · Use fromWei to convert your bigNumber to ether and then convert it to Number. Be aware that unnecessary 0 after the floating point will not be displayed. In web3 ^1.0 it may change to web3.utils.fromWei instead of web3.fromWei doc. Note that truffle ^5.0 uses web3 ^1.0. If you have a different token decimal Let's say 6. WebNov 8, 2024 · The issue is that ether (and most ERC20 tokens) only support 18 decimals. So what I use is a simple function to round the string down before I pass it to ethers.utils.parseEther function roundCryptoValueString ( str , decimalPlaces = 18 ) { const arr = str . split ( "." WebDec 6, 2024 · So let's say I have a big number "6436466091886065000000" and quantity as a number that is 0.03306254672760674. I still don't really understand how to multiply both values without loosing accuracy. And also how I can use BigNumber.mul that only accepts a string Sign up for free to join this conversation on GitHub . Already have an … gammage \u0026 burnham law offices